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You perform static retinoscopy at 67 cm and reach neutrality with +4.00 DS in the trial frame. What is the patient’s approximate refractive error?
A. +2.50 DS ✔️
B. +3.50 DS
C. +2.00 DS
D. +4.00 DS
Explanation: At 67 cm, the working distance is +1.50 D. Subtract this from the neutralizing lens: +4.00 − 1.50 = +2.50 DS hyperopia.
